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Math Combinations Help


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A standard deck or cards consists of 4 suits of 13 cards each. How many 5-card hands can be dealt that include 4 cards from the same suit and one card from a different suit?


Could someone tell me the answer and explain how you got it?

I got an answer but not sure I got it correct though.

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13C4 x 39C1


You have 13 cards of the same suit and you need to pick 4 of them. => 13C4

You then have 39 cards left and you need to pick one of them. => 39C1


You multiply them together because for the outcome, you want 4 cards of the same suit AND a card of another suit.

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