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Thunderclaw

Math Combinations Help

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A standard deck or cards consists of 4 suits of 13 cards each. How many 5-card hands can be dealt that include 4 cards from the same suit and one card from a different suit?

 

Could someone tell me the answer and explain how you got it?

I got an answer but not sure I got it correct though.

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13C4 x 39C1

 

You have 13 cards of the same suit and you need to pick 4 of them. => 13C4

You then have 39 cards left and you need to pick one of them. => 39C1

 

You multiply them together because for the outcome, you want 4 cards of the same suit AND a card of another suit.

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Sorry, shouldn't have done this late at night. You then multiply your answer by 4 because it doesn't ask for a specific suit. eg it can be 4 spades + 1 diamond or 4 hearts + 1 spade.

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